**Demystifying the Java Code: Filtering Prime Numbers with Streams**

Have you ever encountered a piece of Java code that left you scratching your head? Fear not, for today we’re going to unravel the intricacies of a seemingly complex code snippet that filters prime numbers using Java streams. Whether you’re a seasoned programmer or just starting your coding journey, this article will break down the code step by step, making it crystal clear even for java beginners.

## The Code Explained: Filtering Prime Numbers

List<Integer> numbers = Arrays.asList(2, 3, 4, 5, 6, 7); List<Integer> primes = numbers.stream() .filter(n -> IntStream.rangeClosed(2, (int) Math.sqrt(n)) .allMatch(i -> n % i != 0)) .collect(Collectors.toList());

**Understanding the Purpose**

This java code snippet serves a specific purpose: to filter out prime numbers from a given list of integers. Let’s break it down further to comprehend the mechanics behind each step.

**Step 1: Creating the List**

At the beginning of the java code, we create a list of integers named `numbers`

. In this example, we have included a series of integers, namely 2, 3, 4, 5, 6, and 7. These are the numbers from which we want to filter out the prime numbers.

**Step 2: The Stream**

The real magic begins with the introduction of Java streams. We call the `stream()`

method on the `numbers`

list, which transforms it into a stream of elements. Streams allow us to perform operations on the elements in a concise and functional manner.

**Step 3: Filtering with Lambda**

In this step, we utilize the `filter`

operation provided by streams. Within the `filter`

operation, we define a lambda expression that takes an integer `n`

as input and returns a boolean value. The lambda expression checks whether all the values within a range satisfy a specific condition.

**Step 4: Prime Number Check**

The heart of the java code lies within the lambda expression. We use the `IntStream.rangeClosed()`

method to generate a range of integers from 2 to the square root of `n`

. For each number `i`

in this range, we check whether `n`

is divisible evenly by `i`

using the expression `n % i != 0`

. If this condition holds true for all values of `i`

, then `n`

is deemed a prime number.

**Step 5: Collecting the Results**

Once the filtering is complete, the `.collect(Collectors.toList())`

operation gathers the prime numbers obtained from the stream and stores them in the `primes`

list. This list now holds the prime numbers extracted from the original `numbers`

list.

**Conclusion**

Congratulations! You’ve successfully demystified the given Java code snippet that filters prime numbers using streams. By breaking down each step and explaining the purpose behind it, we’ve made the complex code easy to understand for both beginners and experienced programmers alike.

Remember, Java streams are a powerful tool for processing data in a functional and elegant manner. By mastering the art of stream operations, you’ll be well-equipped to tackle a wide range of coding challenges.